What's your favourite paradox?

[Emil]

God is not almighty.
God cannot create a stone, so heavy, he cannot life it himself.

A. If he could create such a stone, he could not lift it, losing his almightyness
B. He cannot create such a stone, losing his almightyness

100% true

But wouldn't it just be impossible for the ROCK to be so heavy that God can't lift it?
checkmate atheists

[mgdwszx]

I have a few;

This is just something to make one think: 0.999... (0.9 recurring) = 1. Do you agree?

Did this recently as an addition to one of the topics I'm studying:
If 0.999... = x
9.999... = 10x
10x - x would give (9.999... - 0.999...) 9.
9x = 9 so x = 1.

[Arkten]

God is not almighty.
God cannot create a stone, so heavy, he cannot life it himself.

A. If he could create such a stone, he could not lift it, losing his almightyness
B. He cannot create such a stone, losing his almightyness

100% true

But wouldn't it just be impossible for the ROCK to be so heavy that God can't lift it?
checkmate atheists

No, it would not. It is a Rock. It has no life, no will.

[Arkten]

I have a few;

This is just something to make one think: 0.999... (0.9 recurring) = 1. Do you agree?

Did this recently as an addition to one of the topics I'm studying:
If 0.999... = x
9.999... = 10x
10x - x  would give (9.999... - 0.999...) 9.
9x = 9 so x = 1.

IT IS JUST A THEORY...

Well, first of, multiplying something by ten always requires the number to end with a zero, (this does not matter for now as you see in the example, just wanted to point that out)
If 0.999... = x
then 10x = 9.999...0 <- This zero is meaningless as it stands behind a comma
so 10x - x would result in (9.999...0 - 0.999... = 9)
9x = 9 so x = 1

But, doesnt multiplying by ten also mean that moving its content forward by one decimal? Meaning that,
10x = 9.999...0 <- On this xth position (the theoritically last position of this not ending number) is a zero
01x = 0.999...9 <- On the same position (the theoritically last position of this not ending number) must be a nine
so 10x - x would result in (9.999...0 - 0,999...9 = 8,999...1)
9x = 8,999...1 so x = 0,999...9

These are my thoughts about this topic, this is pure theory.

[aviator]

Did this recently as an addition to one of the topics I'm studying:
If 0.999... = x
9.999... = 10x
10x - x would give (9.999... - 0.999...) 9.
9x = 9 so x = 1.

Exactly, it seems quite unintuitive but definitely true.

God is not almighty.
God cannot create a stone, so heavy, he cannot life it himself.

A. If he could create such a stone, he could not lift it, losing his almightyness
B. He cannot create such a stone, losing his almightyness

100% true

Indeed, the omnipotence paradox, one of the many arguments against the existence of God.

[aviator]

IT IS JUST A THEORY...

Well, first of, multiplying something by ten always requires the number to end with a zero, (this does not matter for now as you see in the example, just wanted to point that out)
If 0.999... = x
then 10x = 9.999...0 <- This zero is meaningless as it stands behind a comma
so 10x - x would result in (9.999...0 - 0.999... = 9)
9x = 9 so x = 1

But, doesnt multiplying by ten also mean that moving its content forward by one decimal? Meaning that,
10x = 9.999...0 <- On this xth position (the theoritically last position of this not ending number) is a zero
01x = 0.999...9 <- On the same position (the theoritically last position of this not ending number) must be a nine
so 10x - x would result in (9.999...0 - 0,999...9 = 8,999...1)
9x = 8,999...1 so x = 0,999...9

These are my thoughts about this topic, this is pure theory.

If you're interested, I've attached 2 links about this. These aren't exactly "rigorous" proofs, because if you were to do that you'd be getting into degree level maths. One of them touches on your point about multiplying by 10. Effectively, multiplying 0.999... which has an infinite number of nines by 10 to get 9.999... will still have an infinite number of nines. The first link touches on this. The second one is a little discussion involving infinite sums as 0.999... can also be represented by the infinite sum from 1 to +∞ of  9/(10)^n, the sum's limit is 1.

You can also follow the same method as before: 1/9=0.111... (x9) => 9/9=0.999... => 1=0.999..., albeit these do have assumptions, but a rigorous proof of this would be almost impossible for people without completing a university course in maths to understand.

https://www.physicsforums.com/insights/w...are-equal/
https://www.physicsforums.com/threads/is...-1.542160/

[Greed^]

I have a few;

This is just something to make one think: 0.999... (0.9 recurring) = 1. Do you agree?

Did this recently as an addition to one of the topics I'm studying:
If 0.999... = x
9.999... = 10x
10x - x  would give (9.999... - 0.999...) 9.
9x = 9 so x = 1.

You must lack some brain cells
if 1 x = 0.999, then 10 * x = 9.99
now 9.99 - 0.999 = 8.991
You could also do 9*0.999 = 8.991

Basic math really

[Arkten]

I have a few;

This is just something to make one think: 0.999... (0.9 recurring) = 1. Do you agree?

Did this recently as an addition to one of the topics I'm studying:
If 0.999... = x
9.999... = 10x
10x - x  would give (9.999... - 0.999...) 9.
9x = 9 so x = 1.

You must lack some brain cells
if 1 x = 0.999, then 10 * x = 9.99
now 9.99 - 0.999 = 8.991
You could also do 9*0.999 = 8.991

Basic math really

Basically what i showed, but with a finite amount of digits

[DarkN00b]

Religion is like FL. 

You believe Soul to do something

He doesn't.

[aviator]

You must lack some brain cells
if 1 x = 0.999, then 10 * x = 9.99
now 9.99 - 0.999 = 8.991
You could also do 9*0.999 = 8.991

Basic math really

Indeed, he's the one lacking brain cells... I'm sure you noticed the ellipsis in his solution, see my post immediately above yours about this.