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10-05-2018, 05:01 PM
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(10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
use demos and plot both functions, although you’re gonna have to put the second function into ax+bx+c form first
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10-05-2018, 07:26 PM
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(10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
I can't do maths I'm shit lol
pls rep so i can be famous like soulripper
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10-05-2018, 08:29 PM
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(10-05-2018, 05:01 PM)juicyorange Wrote: (10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
use demos and plot both functions, although you’re gonna have to put the second function into ax+bx+c form first
reading this gave me a headache
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10-05-2018, 10:27 PM
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(10-05-2018, 05:01 PM)juicyorange Wrote: (10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
use demos and plot both functions, although you’re gonna have to put the second function into ax+bx+c form first
everyone else joking around not realizing this is a serious matter, thanks daddy Juicyapple you're the best
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The La-lie-lu-le-lo remain.
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10-12-2018, 12:51 PM
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(10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
I mean like ... haven’t you heard about Photomath? Hold your camera over your math and wait for it to get the answer. Works on my homework .... (PS: I only got electrify homework within math, so I do not have to punt it how i managed to get to the answer.)
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(10-12-2018, 12:51 PM)Zona Wrote: (10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
I mean like ... haven’t you heard about Photomath? Hold your camera over your math and wait for it to get the answer. Works on my homework .... (PS: I only got electrify homework within math, so I do not have to punt it how i managed to get to the answer.)
Wow admitting to cheating on Math homework are we? I'll be sure to bring this up at the next board meeting.
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10-13-2018, 10:52 AM
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(10-12-2018, 12:51 PM)Zona Wrote: (10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
I mean like ... haven’t you heard about Photomath? Hold your camera over your math and wait for it to get the answer. Works on my homework .... (PS: I only got electrify homework within math, so I do not have to punt it how i managed to get to the answer.)
You may or may not of just saved my life.
pls rep so i can be famous like soulripper
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10-13-2018, 11:30 AM
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(10-05-2018, 03:03 PM)Emil Wrote: can someone help me with my homework how do i find the intersection between something like f(x)=2x-4 and a line that crosses over the points a a=(-1, 5) and b=(1, 9)
so you need to find the gradient of the second line first, you already have the points a and b so first do:
m=(y2-y1)/(x2-x1) = (9-5)/(1--1) = 4/2 = 2
so now that you have the gradient, use the equation y-b=m(x-a) and plot either a or b into the equation:
y-b=m(x-a)
y-5=2(x--1)
y-5=2x+2
y=2x+7
now that you have the second equation, to find the intersection make both the equations equal to each other and find x:
2x+7=2x-4
2x=2x-11
x=0
since x=0, you have shown that these lines don't intersect and you can plot a graph as well for y=2x+7 vs y=2x-4 to prove it. they also won't intersect because they both have the same gradient.
can't remember if this is the way you do it but i think it is
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