09-15-2018, 05:30 PM
(This post was last modified: 09-01-2022, 01:07 AM by Fearless Community.
Edit Reason: Checked Encoding
)
hi so basically:
"using the first three terms of the expansion (1-2x)^12 and the substitution x= 0.01 gives an approximate value for 0.98^12"
anyone want to help out it is non calculator and we get given the binomial theorem
"using the first three terms of the expansion (1-2x)^12 and the substitution x= 0.01 gives an approximate value for 0.98^12"
anyone want to help out it is non calculator and we get given the binomial theorem