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03-19-2012, 06:04 AM
(This post was last modified: 09-01-2022, 01:01 AM by Fearless Community.
Edit Reason: Checked Encoding
)
Lol any help would be appreciated, if there is anyone good at Chemistry.
Here is what i did:
5.52gCu * 1 mol Cu/ 63.5g Cu = 0.09mol Cu
10.1gS 8 1 mol S/ 2 mol Cu = 0.045 mol S
Sulfur = Excess Reagent
Copper = Limited Reagent
Limited Reactants
1. Given the following reaction, a student heated 5.52g of copper and 10.1 g of Sulfur.
2Cu (g) + 1S (s) ---> 1Cu2S (s)
a. What is the limited reagent?
b. What mass of the product Cu2S is formed?
2Cu (g) + 1S (s) ---> 1Cu2S (s)
a. What is the limited reagent?
b. What mass of the product Cu2S is formed?
c. How much of the excess reactant will be left over?
Here is what i did:
5.52gCu * 1 mol Cu/ 63.5g Cu = 0.09mol Cu
10.1gS 8 1 mol S/ 2 mol Cu = 0.045 mol S
Sulfur = Excess Reagent
Copper = Limited Reagent