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12-14-2011, 10:39 PM
(This post was last modified: 09-01-2022, 01:01 AM by Fearless Community.
Edit Reason: Checked Encoding
)
"2. If a mother has blood type B and her child has blood type 0;
What does the father then posses? Make a crossing scheme."
I've done these in High School Biology, so allow me to help you out. '
This is indeed a case of Mendelian inheritance (I'd think, can't think of it being anything else), but instead of the recessive/dominant gene-pair, Blood type is one of the aspects of a human that is inherited via Co-affection of the two genes inherited.
In short, both genes contribute, instead of the other one directly ruling over the outcome. Now, to the task itself.
A blood type "B" will appear if the Gene pairs are either of the following, it doesn't matter which parent they are from:
1. B and B
2. B and 0
Because the Child has the bloodtype of 0, which is only possible with an inherited a genotype:
0 and 0
Because the child has to inherit an 0-gene from their mother to be of the 0-bloodtype, there's no other choice for the mother's genotype as:
B and 0, out of which the child inherits the 0-part.
To be of 0-bloodtype, the child needs to inherit ANOTHER 0-gene from their father. Therefore, the possible genotypes for the father are ANY that include AT LEAST one 0-gene, because the child will RANDOMLY inherit either one. :
1. A and 0
2. B and 0
3. 0 and 0
With the aforementioned genotypes, there IS A POSSIBILITY OF THE CHILD INHERITING TWO 0-GENES, ONE FROM EACH PARENT.
Therefore, you'll need to make a total of 3 crossing schemes. ^^
I hope that helped, I tried to make it as understandable as possible.
EDIT: It's also relatively easy to put these in a cross scheme. Have the mothers genes in a vertical column, and the fathers in a horizontical one, and add them together! Allow me to demonstrate. In this case, the father has the Genotype A and 0:
A 0
B [AB] [B0]
0 [A0] [00] <- This is what you need to establish, the possibility of inheriting an 0-Bloodtype.
Now, just do the following to the other possible genotypes of the father and you're done!
What does the father then posses? Make a crossing scheme."
I've done these in High School Biology, so allow me to help you out. '
This is indeed a case of Mendelian inheritance (I'd think, can't think of it being anything else), but instead of the recessive/dominant gene-pair, Blood type is one of the aspects of a human that is inherited via Co-affection of the two genes inherited.
In short, both genes contribute, instead of the other one directly ruling over the outcome. Now, to the task itself.
A blood type "B" will appear if the Gene pairs are either of the following, it doesn't matter which parent they are from:
1. B and B
2. B and 0
Because the Child has the bloodtype of 0, which is only possible with an inherited a genotype:
0 and 0
Because the child has to inherit an 0-gene from their mother to be of the 0-bloodtype, there's no other choice for the mother's genotype as:
B and 0, out of which the child inherits the 0-part.
To be of 0-bloodtype, the child needs to inherit ANOTHER 0-gene from their father. Therefore, the possible genotypes for the father are ANY that include AT LEAST one 0-gene, because the child will RANDOMLY inherit either one. :
1. A and 0
2. B and 0
3. 0 and 0
With the aforementioned genotypes, there IS A POSSIBILITY OF THE CHILD INHERITING TWO 0-GENES, ONE FROM EACH PARENT.
Therefore, you'll need to make a total of 3 crossing schemes. ^^
I hope that helped, I tried to make it as understandable as possible.
EDIT: It's also relatively easy to put these in a cross scheme. Have the mothers genes in a vertical column, and the fathers in a horizontical one, and add them together! Allow me to demonstrate. In this case, the father has the Genotype A and 0:
A 0
B [AB] [B0]
0 [A0] [00] <- This is what you need to establish, the possibility of inheriting an 0-Bloodtype.
Now, just do the following to the other possible genotypes of the father and you're done!