#EdexcelMaths

[Adman]

I've tried looking for the question and from what I've gathered it tells you hannah has n sweets in which 6 of them are orange. The probability of picking two orange sweets one after the other is 1/3.

So if you define the probability of picking an orange sweet as 6/n and then the probability of picking another orange sweet (without replacement) as 5/(n-1) then multiplying these together will equal 1/3.

6/n x 5/(n-1) = 1/3
30/n(n-1) = 1/3
30 = 1/3 x n(n-1)
90 = n(n-1)
n^2 - n - 90 = 0

Is this what part (a) was about? Then solving to get n=10?

I can see why the first part is pretty tricky for a GCSE paper.

edit: also sorry if it's hard to follow the working, maths looks pretty shit without proper formatting